5/x+4/(x+3)=8/(x^2+3x)

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Solution for 5/x+4/(x+3)=8/(x^2+3x) equation: 


D( x )

x^2+3*x = 0

x = 0

x+3 = 0

x^2+3*x = 0

x^2+3*x = 0

x^2+3*x = 0

DELTA = 3^2-(0*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)-3)/(1*2) or x = (-9^(1/2)-3)/(1*2)

x = 0 or x = -3

x = 0

x = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:0) U (0:+oo)

4/(x+3)+5/x = 8/(x^2+3*x) // - 8/(x^2+3*x)

4/(x+3)-(8/(x^2+3*x))+5/x = 0

4/(x+3)-8*(x^2+3*x)^-1+5/x = 0

4/(x+3)-8/(x^2+3*x)+5/x = 0

x^2+3*x = 0

x^2+3*x = 0

x*(x+3) = 0

x+3 = 0 // - 3

x = -3

x*(x+3) = 0

4/(x+3)-8/(x*(x+3))+5/x = 0

(4*x)/(x*(x+3))-8/(x*(x+3))+(5*(x+3))/(x*(x+3)) = 0

5*(x+3)+4*x-8 = 0

4*x+5*x-8+15 = 0

9*x+7 = 0

(9*x+7)/(x*(x+3)) = 0

(9*x+7)/(x*(x+3)) = 0 // * x*(x+3)

9*x+7 = 0

9*x+7 = 0 // - 7

9*x = -7 // : 9

x = -7/9

x = -7/9

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